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- .geometry "version 0.1";
- v1 = .free(0.003774, -0.098113, .yellow, "1");
- v2 = .free(-0.241509, 0.732075, .yellow, "2");
- v4 = .free(0.714674, -0.125, .green, "4");
- c1 = .c.vv(v1, v4, .yellow);
- v5 = .vonc(c1, -0.702567, -0.013353, .yellow, .plus, "3");
- l1 = .l.vv(v1, v2, .yellow);
- l2 = .l.vv(v1, v5, .yellow);
- l3 = .l.vlpar(v5, l1, .invisible, .longline);
- l4 = .l.vlpar(v2, l2, .invisible);
- v6 = .v.ll(l4, l3, .yellow);
- l5 = .l.vv(v2, v6, .yellow);
- v7 = .v.ll(l3, l2, .yellow);
- l6 = .l.vv(v5, v6, .yellow);
- l7 = .l.vv(v5, v2, .yellow);
- l8 = .l.vv(v1, v6, .yellow);
- v8 = .v.ll(l8, l7, .smear);
- .text("Hinged Parallelogram:");
- .text("");
- .text("Choose two arbitrary points 1 and 2, and draw a circle about");
- .text("point 1. Choose point 3 anywhere on the circle. Construct the");
- .text("parallelogram using points 1, 2, and 3, and find the intersection");
- .text("of its diagonals. As point 3 is moved around the circle, the");
- .text("intersection of the diagonals sweeps out a circle. Try different");
- .text("points 1, 2, and 4 to get different circles.");
-